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Fuller's initial value problem: Difference between revisions

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<math>
<math>
\begin{array}{llcl}
\begin{array}{llcl}
  \displaystyle \min_{x, w} & \int_{0}^{1} x_0^2 & \; \mathrm{d} t + (x(t_f)-x_T)^2 \\[1.5ex]
  \displaystyle \min_{x, w} & \int_{t_0}^{t_f} x_0^2 \; &\mathrm{d} t& + (x(t_f)-x_T)^2 \\[1.5ex]
  \mbox{s.t.} & \dot{x}_0 & = & x_1, \\
  \mbox{s.t.} & \dot{x}_0 & = & x_1, \\
  & \dot{x}_1 & = & 1 - 2 \; w, \\[1.5ex]
  & \dot{x}_1 & = & 1 - 2 \; w, \\[1.5ex]
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== Parameters ==
== Parameters ==


We use <math>x_S = x_T = (0.01, 0)^T</math>.
We use <math>x_S = x_T = (0.01, 0)^T</math> and <math>(t_0,t_f) = (0,1)</math>.


== Reference Solutions ==
== Reference Solutions ==

Latest revision as of 22:26, 8 January 2018

Fuller's initial value problem
State dimension: 1
Differential states: 2
Discrete control functions: 1
Interior point equalities: 2

This site describes a Fuller's problem variant with no terminal constraints and additional Mayer term for penalizing deviation from given reference values.

Mathematical formulation

For t[t0,tf] almost everywhere the mixed-integer optimal control problem is given by

minx,wt0tfx02dt+(x(tf)xT)2s.t.x˙0=x1,x˙1=12w,x(0)=xS,w(t){0,1}.

Parameters

We use xS=xT=(0.01,0)T and (t0,tf)=(0,1).

Reference Solutions

If the problem is relaxed, i.e., we demand that w(t) be in the continuous interval [0,1] instead of the binary choice {0,1}, the optimal solution can be determined by means of direct optimal control.

The optimal objective value of the relaxed problem with nt=6000,nu=150 is 1.45412214e05. The objective value of the binary controls obtained by Combinatorial Integral Approimation (CIA) is 2.40273813e05.