Oil Shale Pyrolysis: Difference between revisions
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{{Dimensions | {{Dimensions | ||
|nd = | |nd = 4 | ||
|nx = | |nx = 4 | ||
|nu = 1 | |nu = 1 | ||
|nw = 0 | |nw = 0 | ||
|nc = 4 | |nc = 4 | ||
|nre = | |nre = 0 | ||
}} | }} | ||
| Line 22: | Line 22: | ||
Each reaction is governed by a rate described by: | Each reaction is governed by a rate described by: | ||
<math>k_i = k_{i0} \exp{-E_i/RT}, (i=1,2,3,4,5)</math> | <math>k_i = k_{i0} \exp{\left(-E_i/RT\right)}, (i=1,2,3,4,5)</math> | ||
== Mathematical formulation == | == Mathematical formulation == | ||
<math> | <math> | ||
\begin{array}{ | \begin{array}{llll} | ||
\displaystyle \ | \displaystyle \max_{T} & \displaystyle x_2(t_N) \\[1.5ex] | ||
\mbox{s.t.} & \displaystyle \dot{x}_1 &= -k_1x_1-(k_3+k_4+k_5)x_1x_2\\ | \mbox{s.t.} & \displaystyle \dot{x}_1 &=& -k_1x_1-(k_3+k_4+k_5)x_1x_2\\ | ||
& \displaystyle \dot{x}_2 &= k_1x_1-k_2x_2 + k_3x_1x_2\\ | & \displaystyle \dot{x}_2 &=& k_1x_1-k_2x_2 + k_3x_1x_2\\ | ||
& \displaystyle \dot{x}_3 &= k_2x_2 + k_4x_1x_2\\ | & \displaystyle \dot{x}_3 &=& k_2x_2 + k_4x_1x_2\\ | ||
& \displaystyle \dot{x}_4 &= k_5x_1x_2\\ | & \displaystyle \dot{x}_4 &=& k_5x_1x_2\\ | ||
& \displaystyle k_i &= a_i | & \displaystyle k_i &=& a_i \exp\left(-\frac{b_i}{RT}\right),\quad \forall i\in \{1,\dots,5\} \\[1.5ex] | ||
& \displaystyle t &\in \left[t_0,t_N\right] \\ | & \displaystyle t &\in& \left[t_0,t_N\right] \\ | ||
& \displaystyle T(t) &\in \left[698.15K,748.15K\right]\\ | & \displaystyle T(t) &\in& \left[698.15K,748.15K\right]\\ | ||
& \displaystyle x(t_0) &= (1,0,0,0)^T\\ | & \displaystyle x(t_0) &=& (1,0,0,0)^T\\ | ||
\end{array} | \end{array} | ||
</math> | </math> | ||
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|- | |- | ||
|<math>b_1</math> | |<math>b_1</math> | ||
|<math>\exp{8.86}</math> | |<math>\exp{(8.86)}</math> | ||
|- | |- | ||
|<math>b_2</math> | |<math>b_2</math> | ||
|<math>\exp{24.25}</math> | |<math>\exp{(24.25)}</math> | ||
|- | |- | ||
|<math>b_3</math> | |<math>b_3</math> | ||
|<math>\exp{23.67}</math> | |<math>\exp{(23.67)}</math> | ||
|- | |- | ||
|<math>b_4</math> | |<math>b_4</math> | ||
|<math>\exp{18.75}</math> | |<math>\exp{(18.75)}</math> | ||
|- | |- | ||
|<math>b_5</math> | |<math>b_5</math> | ||
|<math>\exp{20.7}</math> | |<math>\exp{(20.7)}</math> | ||
|} | |} | ||
| Line 108: | Line 108: | ||
|} | |} | ||
== | == Solutions == | ||
* [[:Category:Gekko | GEKKO Python code]] at [[Oil shale pyrolysis (GEKKO)]] | |||
== References == | == References == | ||
Latest revision as of 13:53, 16 October 2025
| Oil Shale Pyrolysis | |
|---|---|
| State dimension: | 4 |
| Differential states: | 4 |
| Continuous control functions: | 1 |
| Discrete control functions: | 0 |
| Path constraints: | 4 |
| Interior point equalities: | 0 |
The following problem is an example from the global optimal control literature and was introduced in [Wen1977]The entry doesn't exist yet.. The process starts with kerogen and is decomposed into pyrolytic bitumen, oil and gas, and residual carbon. The objective is to maximize the fraction of pyrolytic bitumen. There are 5 reactions including:
Each reaction is governed by a rate described by:
Mathematical formulation
Parameters
| Symbol | Initial value () |
| Symbol | Value |
| Symbol | Interval |
| [698.15,748.15] |
Solutions
References
| [Wen1977] | The entry doesn't exist yet. |