Jump to content

Isomerization of Alpha-Pinene problem: Difference between revisions

From mintOC
No edit summary
No edit summary
 
(2 intermediate revisions by the same user not shown)
Line 2: Line 2:
|nz        = 5
|nz        = 5
|np        = 5
|np        = 5
|nc        = 5
}}<!-- Do not insert line break here or Dimensions Box moves up in the layout...
}}<!-- Do not insert line break here or Dimensions Box moves up in the layout...


Line 22: Line 23:
  & \dot{y}_4 & = & \theta_3 y_3,  \\
  & \dot{y}_4 & = & \theta_3 y_3,  \\
  & \dot{y}_5 & = & \theta_4 y_3 - \theta_5 y_5, \\
  & \dot{y}_5 & = & \theta_4 y_3 - \theta_5 y_5, \\
  & \theta_i & \geq & 0.
  & \theta_i & \geq & 0 \quad i = 1,...,5.
\end{array}  
\end{array}  
</math>
</math>
Line 41: Line 42:
[[Category:ODE model]]
[[Category:ODE model]]
[[Category:DAE model]]
[[Category:DAE model]]
[[Category:Chemical engineering]]

Latest revision as of 19:22, 29 September 2016

Isomerization of Alpha-Pinene problem
Algebraic states: 5
Continuous control values: 5
Path constraints: 5

The Isomerization of Alpha-Pinene problem tries to determine "reaction coefficients in the thermal isometrization of α-Pinene." (Cite and problem taken from the COPS library)


Mathematical formulation

The problem is given by

minθj=18||y(τj;θ)zj||2s.t.y˙1=(θ1+θ2)y1,y˙2=θ1y1,y˙3=θ2y1(θ3+θ4)y3+θ5y5,y˙4=θ3y3,y˙5=θ4y3θ5y5,θi0i=1,...,5.

Parameters

The values zj are measurements for the concentration for y at time points τ1,...,τ8 and initial conditions are known.

Source Code

Model descriptions are available in